$|x+2| = 12 + (-3) +|-4|$
⇔ $|x+2| = 12 -3 +4$
⇔ $|x+2| = 13$
⇔ \(\left[ \begin{array}{l}x+2=13\\x+2=-13\end{array} \right.\)
⇔ \(\left[ \begin{array}{l}x=13-2\\x=-13-2\end{array} \right.\)
⇔ \(\left[ \begin{array}{l}x=11\\x=-15\end{array} \right.\)
Vậy $x=-15$ hoặc $x=11$
