`x/2 = y/3 ; y/4 = z/5` `\text{và}` `x + y - z = 10`
`\text{Ta có : }`
`x/2 . 1/4 = y/3 . 1/4 `
`y/4 . 1/3 = z/5 . 1/3`
`=> x/8 = y/12 ; y/12 = z/15` `=> x/8 = y/12 = z/15`
`\text{Ta áp dụng t/c DTSBN : }`
`x/8 = y/12 = y/15 = (x + y - z)/(8 + 12 - 15)` `= 10/5` `=`` 2`
`\text{Suy ra :}`
`x/8 = 2 => x = 8 . 2 = 16`
`y/12 = 2 => y = 12 . 2 = 24`
`z/15 = 2 => z = 15 . 2 = 30`
`\text{Vậy x = 16 ; y = 24 ; z = 30}`
`16 + 24 - 30`
`= 40 - 30 = 10`
`\text{@Sứa}`
`\text{Chúc bạn học tốt ^^ }`
