Lời giải :
`(x-92)^2-10^2=6^2`
`<=>(x-92)^2-100=36`
`<=>(x-92)^2=136`
`<=>(x-92)^2=(\pm 2\sqrt{34})^2`
`<=>` \(\left[ \begin{array}{l}x-92=2\sqrt34\\x-92=-2\sqrt34\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}x=2\sqrt34+92\\x=-2\sqrt34+92\end{array} \right.\)
Vậy `x \in {2\sqrt34 + 92 ; -2\sqrt34 + 92}`
