a, Ta có :
\(\left|x-2\right|\le2\)
Mà \(\left|x-2\right|\ge0\)
\(\Leftrightarrow\left[{}\begin{matrix}\left|x-2\right|=0\\\left|x-2\right|=1\\\left|x-2\right|=2\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\\left[{}\begin{matrix}x-2=1\\x-2=-1\end{matrix}\right.\\\left[{}\begin{matrix}x-2=2\\x-2=-2\end{matrix}\right.\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=2\\\left[{}\begin{matrix}x=3\\x=-1\end{matrix}\right.\\\left[{}\begin{matrix}x=4\\x=0\end{matrix}\right.\end{matrix}\right.\)
Vậy =-
b, \(\left|x-3\right|\le0\)
Mà \(\left|x-3\right|\ge0\)
\(\Leftrightarrow x-3=0\)
\(\Leftrightarrow x=3\)
Vậy =
c, tương tự như a
