a) $\dfrac{3}{2}-(x-\dfrac{7}{3})=|-\dfrac{3}{4}-\dfrac{9}{8}|$
$\dfrac{3}{2}-(x-\dfrac{7}{3})=\dfrac{15}{8}$
$x-\dfrac{7}{3}=\dfrac{3}{2}-\dfrac{15}{8}$
$x-\dfrac{7}{3}=-\dfrac{3}{8}$
$⇒x=-\dfrac{3}{8}+\dfrac{7}{3}=\dfrac{47}{24}$
b) $\dfrac{5}{2}-(\dfrac{3}{2}-\dfrac{7}{3}+x)=\dfrac{8}{15}-(\dfrac{1}{4}-\dfrac{7}{10})$
$\dfrac{5}{2}-(-\dfrac{5}{6}+x)=\dfrac{8}{15}+\dfrac{9}{20}=\dfrac{59}{60}$
$-\dfrac{5}{6}+x=\dfrac{5}{2}-\dfrac{59}{60}=\dfrac{91}{60}$
$x=\dfrac{91}{60}+\dfrac{5}{6}=\dfrac{47}{20}$
$⇒x=\dfrac{59}{60}-\dfrac{10}{3}=-\dfrac{47}{20}$
c) $3.(\dfrac{1}{2}-x)+\dfrac{1}{3}=\dfrac{7}{6}-x$
$\dfrac{3}{2}-3x+\dfrac{1}{3}-\dfrac{7}{6}+x=0$
$(\dfrac{3}{2}-\dfrac{7}{6}+\dfrac{1}{3})+(-3x+x)=0$
$\dfrac{2}{3}-2x=0$
$2x=\dfrac{2}{3}$
$⇒x=\dfrac{2}{3}:2=\dfrac{1}{3}$
d) $\dfrac{1}{2}(x-3)+\dfrac{2}{7}.(7x-4)=10$
$\dfrac{1}{2}x-\dfrac{3}{2}+2x-\dfrac{8}{7}=10$
$(\dfrac{1}{2}x+2x)+(-\dfrac{3}{2}-\dfrac{8}{7})=10$
$\dfrac{5}{2}x-\dfrac{37}{14}=10$
$\dfrac{5}{2}x=10+\dfrac{37}{14}=\dfrac{177}{14}$
$x=\dfrac{177}{14}:\dfrac{5}{2}=\dfrac{177}{35}$
