Đáp án:
`a, x ² - 7x = 0`
`⇔ x(x-7)=0`
\(⇔ \left[ \begin{array}{l}x=0\\x-7=0\end{array} \right.\)
\(⇔ \left[ \begin{array}{l}x=0\\x=7\end{array} \right.\)
`\text{S = {0 ; 7}}`
`b, x^2 - x + 1/4 = 0`
`⇔ x^2 - 2. 1/2 . x + (1/2)^2 = 0`
`⇔ (x-1/2)^2 = 0`
`⇔ x - 1/2 = 0`
`⇔ x = 1/2`
`\text{S = }{1/2}`