\(\left( {x + \frac{1}{2}} \right).\left( {\frac{2}{3} - 2x} \right) = 0 \Leftrightarrow \left[ {\begin{array}{*{20}{c}} {x + \frac{1}{2} = 0}\\ {\frac{2}{3} - 2x = 0} \end{array}} \right.\)
\( \Leftrightarrow \left[ {\begin{array}{*{20}{c}} {x = \frac{{ - 1}}{2}}\\ {2x = \frac{2}{3}} \end{array}} \right. \Leftrightarrow \left[ {\begin{array}{*{20}{c}} {x = \frac{{ - 1}}{2}}\\ {x = \frac{1}{3}} \end{array}} \right.\)
vậy \(x=\dfrac{-1}{2};x=\dfrac{1}{3}\)
