x10 = x2
=> x10 - x2 = 0
=> x2.(x8 - 1) = 0
\(\Rightarrow\left[\begin{array}{nghiempt}x^2=0\\x^8-1=0\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}x=0\\x^8=1\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}x=0\\x=1\\x=-1\end{array}\right.\)
Vậy \(x\in\left\{0;1;-1\right\}\)