Đáp án+Giải thích các bước giải:
`e)5x(x-2)-x+2=0`
`<=>5x(x-2)-(x-2)=0`
`<=>(5x-1)(x-2)=0`
`<=>[(5x-1=0),(x-2=0):}`
`<=>[(x=1/5),(x=2):}`
Vậy `x\in{1/2;2}`
`f)4x(x+1)=8(x+1)`
`<=>4x(x+1)-8(x+1)=0`
`<=>(x+1)(4x-8)=0`
`<=>4(x+1)(x-2)=0`
`<=>[(x+1=0),(x-2=0):}`
`<=>[(x=-1),(x=2):}`
Vậy `x\in{-1;2}`
`g)x(2x+1)+1/3+2/3 x=0`
`<=>x(2x+1)+1/3(1+2x)=0`
`<=>(2x+1)(x+1/3)=0`
`<=>[(2x+1=0),(x+1/3=0):}`
`<=>[(x=-1/2),(x=-1/3):}`
Vậy `x\in{-1/2;-1/3}`
`h)x(x-4)+(x-4)^2=0`
`<=>(x-4)(x+x-4)=0`
`<=>(x-4)(2x-4)=0`
`<=>2(x-4)(x-2)=0`
`<=>[(x-4=0),(x-2=0):}`
`<=>[(x=4),(x=2):}`
Vậy `x\in{4;2}`
