TH1 : \(x\le-3\)
\(\Rightarrow\left|x+3\right|+\left|x-1\right|=-x-3-x+1=5\\ \Rightarrow-2x-2=5\\ \Rightarrow x=\dfrac{-7}{2}\)
TH2: \(x\ge1\)
\(\Rightarrow\left|x+3\right|+\left|x-1\right|=x+3+x-1=5\\ \Rightarrow2x=3\\ \Rightarrow x=\dfrac{3}{2}\)
TT xét TH3: -3