$(x- \dfrac{5}{12})( \dfrac{9}{29}) = \dfrac{-6}{29}$
$⇔ x- \dfrac{5}{12} = \dfrac{-6}{29} : \dfrac{9}{29}$
$⇔ x - \dfrac{5}{12} = \dfrac{-6.29}{29.9}$
$⇔ x - \dfrac{5}{12} = \dfrac{-2}{3}$
$⇔ x = \dfrac{-3}{12}$
$⇔ x= \dfrac{-1}{4}$
Vậy $x = \dfrac{-1}{4}$