\(\left|5-x\right|-17=13\)
th1: \(5-x\ge0\Leftrightarrow x\le5\)
\(\Rightarrow\left|5-x\right|-17=13\Leftrightarrow5-x-17=13\Leftrightarrow x=5-17-13\)
\(\Leftrightarrow x=-25\left(tmđk\right)\)
th2: \(5-x< 0\Leftrightarrow x>5\)
\(\Rightarrow\left|5-x\right|-17=13\Leftrightarrow-\left(5-x\right)-17=13\Leftrightarrow-5+x-17=13\)
\(\Leftrightarrow x=13+17+5\Leftrightarrow x=35\left(tmđk\right)\)
vậy \(x=-25;x=35\)