a) \(\left|x\right|=5\Rightarrow x=5\) hoặc x = -5
b) |x| = -5 \(\Rightarrow\) x ko có vì |x| \(\ge\) 0
c) |x| = 0 \(\Rightarrow\) x = 0
d) |x + \(\dfrac{1}{3}\)| - 4 = -1
⇔ |x + \(\dfrac{1}{3}\)| = 3
⇔ \(\left\{{}\begin{matrix}x+\dfrac{1}{3}=3\\x+\dfrac{1}{3}=-3\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{8}{3}\\x=-\dfrac{10}{3}\end{matrix}\right.\)