a) $\frac{-1}{2}$. $x$ + $\frac{2}{3}$.$\frac{-5}{4}$ = $\frac{5}{6}$
$\frac{-1}{2}$. $x$ + $\frac{-5}{6}$ = $\frac{5}{6}$
$\frac{-1}{2}$. $x$ = $\frac{5}{6}$-$\frac{-5}{6}$
$\frac{-1}{2}$. $x$ = $\frac{5}{6}$+$\frac{5}{6}$
$\frac{-1}{2}$. $x$ = $\frac{5}{3}$
$x$ = $\frac{5}{3}$ : $\frac{-1}{2}$
$x$ = $\frac{5}{3}$ . (-2)
$x$ = $\frac{-10}{3}$
b) 4-7 .l $x-3$ l = -3
7 .l $x-3$ l = 4-(-3)
7 .l $x-3$ l = 4+3 = 7
l $x-3$ l = 1
⇒\(\left[ \begin{array}{l}x-3=1\\x-3=-1\end{array} \right.\)
⇒\(\left[ \begin{array}{l}x=4\\x=2\end{array} \right.\)
