Đáp án + Giải thích các bước giải:
a)
`|x+1/3|-5=7`
`=>|x+1/3|=12`
`=>` \(\left[ \begin{array}{l}x+\dfrac13=12\\x+\dfrac13=-12\end{array} \right.\)
`=>` \(\left[ \begin{array}{l}x=\dfrac{35}{3}\\x=-\dfrac{37}{3}\end{array} \right.\)
Vậy `x∈{35/3;-37/3}`
b)
`3(x-2)+2/5=4`
`=>3(x-2)=18/5`
`=>x-2=6/5`
`=>x=16/5`
Vậy `x=16/5`