`a)( 3/2x+10 ):2/3=6`
`=> 3/2x + 10 = 6 . 2/3`
`=> 3/2x + 10 = 4`
`=> 3/2x = 4-10`
`=>3/2x = -6`
`=> x = -6 : 3/2`
`=> x = -4`
Vậy `x=-4`
` b) 1/3x-0,5x=0,75`
` => x . (1/3-0,5) = 0,75`
`=> x. (-1)/6 = 0,75`
`=> x = 0,75 : (-1)/6`
`=> x= (-9)/2`
Vậy `x=(-9)/2`
`c) |x+1|=2^2.(-1 1/4)+15`
` => |x+1| = 4.(-5)/4 +15`
`=> |x+1| = -5 + 15`
`=>|x+1| = 10`
`=> x+1=10` hoặc `x+1=-10`
`+) x+1=10 =>x=9`
`+) x+1=-10=>x=-11`
Vậy `x\in{9;-11}`