Em tham khảo nhé:
$\frac{1}{1.3}+$$\frac{1}{3.5}+$$\frac{1}{5.7}+$$\frac{1}{(2x-1)(2x+1)}=$$\frac{49}{99}$
⇔$1-\frac{1}{3}+$$\frac{1}{3}-$$\frac{1}{5}+$$\frac{1}{7}+.....-$$\frac{1}{2x-1}+$$\frac{1}{2x+1}=$$\frac{98}{99}$
⇔$1-\frac{1}{2x+1}=$$\frac{98}{99}$
⇔$\frac{1}{2x+1}=$$\frac{1}{99}$
⇔$2x=1=99$
⇔$2x=98$
⇔$x=49$
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