`(1/2 + 3/4x)^2 = 25/4`
`⇔` \(\left[ \begin{array}{l}{ \dfrac{3}{4}}x + { \dfrac{1}{2}} = { \dfrac{5}{2}}\\{ \dfrac{3}{4}}x + { \dfrac{1}{2}} = -{ \dfrac{5}{2}}\end{array} \right.\)
`⇔` \(\left[ \begin{array}{l}{ \dfrac{3}{4}}x + { \dfrac{1}{2}} - { \dfrac{1}{2}} = { \dfrac{5}{2}} - { \dfrac{1}{2}}\\{ \dfrac{3}{4}}x + { \dfrac{1}{2}} - { \dfrac{1}{2}} = - { \dfrac{5}{2}} - { \dfrac{1}{2}}\end{array} \right.\)
`⇔` \(\left[ \begin{array}{l}{ \dfrac{3}{4}}x = { \dfrac{5}{2}} - { \dfrac{1}{2}}\\{ \dfrac{3}{4}}x = -{ \dfrac{5}{2}} - { \dfrac{1}{2}}\end{array} \right.\)
`⇔ 3/4x = 2`
`⇔ 3/4x = -3`
`⇔` \(\left[ \begin{array}{l}{ \dfrac{\dfrac{3}{4}x}{\dfrac{3}{4}}} = { \dfrac{2}{\dfrac{3}{4}}} \\{ \dfrac{\dfrac{3}{4}x}{\dfrac{3}{4}}} = { \dfrac{-3}{\dfrac{3}{4}}} \end{array} \right.\)
`⇔` \(\left[ \begin{array}{l}x=\dfrac{2}{\dfrac{3}{4}}\\x={ \dfrac{-3}{\dfrac{3}{4}}}\end{array} \right.\)
`x = 8/3`
`x = -4`
\(\left[ \begin{array}{l}x=\dfrac{8}{3}\\x=-4\end{array} \right.\)
Cho mình xin hay nhất nha bạn!!!!!
@Drew Mclntyre
