Giải thích các bước giải:
$\dfrac{x-2}{\dfrac{1}{2}}=\dfrac{\dfrac{1}{8}}{x-2}$
$⇔(x-2)^2=\dfrac{1}{2} .\dfrac{1}{8}$
$⇔(x-2)^2=\dfrac{1}{16}=(±\dfrac{1}{4})^2$
$⇔$ \(\left[ \begin{array}{l}x-2=\dfrac{1}{4}\\x-2=-\dfrac{1}{4}\end{array} \right.\) $⇔$ \(\left[ \begin{array}{l}x=\dfrac{9}{4}\\x=\dfrac{7}{4}\end{array} \right.\)
$\text{Vậy}$ `x∈\{\frac{7}{4};\frac{9}{4}\}`
Học tốt!!!