2,5-$\dfrac{1}{2}$+$\dfrac{3}{4}$=$\dfrac{10}{4}$-$\dfrac{2}{4}$+$\dfrac{3}{4}$=$\dfrac{10-2+3}{4}$=$\dfrac{11}{4}$
Vậy $\dfrac{3}{2}$<x<$\dfrac{11}{4}$
=> $\dfrac{6}{4}$<x<$\dfrac{11}{4}$
=> x={$\dfrac{7}{4}$;$\dfrac{8}{4}$;$\dfrac{9}{4}$;$\dfrac{10}{4}$}