Hệ pt vô nghiệm
$→\dfrac{m}{m²}=\dfrac{-1}{m²-1}\ne \dfrac{1}{2}$
$\dfrac{m}{m²}\ne \dfrac{1}{2}$
$→\dfrac{1}{m}\ne \dfrac{1}{2}$
$→m\ne 2$
$\dfrac{1}{m}=\dfrac{1}{1-m²}$
$→1-m²=m$
$→m²+m-1=0$
$→m=\dfrac{-1+\sqrt{5}}{2}\quad or\quad m=\dfrac{-1-\sqrt{5}}{2}$ (TMĐK: $m\ne 2$)
Hệ pt có vô số nghiệm
$→\dfrac{m}{m²}=\dfrac{-1}{m²-1}=\dfrac{1}{2}$
$\dfrac{1}{m}=\dfrac{1}{2}$
$→m=2$ (1)
$\dfrac{-1}{m²-1}=\dfrac{1}{2}$
$→1-m²=2$
$→m²=-1$ (vô lý) (2)
(1)(2) $→m∈\{\varnothing\}$