Đáp án:
` C = -9x^2 -16x = - (9x^2 +16x) = - [(3x)^2 + 2*3*8/3 + (8/3)^2] + (8/3)^2`
` = - (3x + 8/3)^2 + 64/9`
Ta có ` (3x+8/3)^2 \ge 0`
` => - (3x+8/3)^2 \le 0`
` => - (3x+8/3)^2 + 64/9 \le 64/9`
Vậy ` C_{max} = 64/9`
Dấu `=` xảy ra khi ` 3x +8/3 = 0 => 3x = -8/3 => x = -8/9`