Đáp án:
$\min P=-\dfrac12\Leftrightarrow x=0$
Lời giải:
$P=\dfrac{\sqrt{x}-1}{\sqrt{x}+2}$
$P=\dfrac{\sqrt{x}+2-3}{\sqrt{x}+2}$
$P=\dfrac{\sqrt{x}+2}{\sqrt{x}+2}-\dfrac{3}{\sqrt{x}+2}$
$P=1-\dfrac{3}{\sqrt{x}+2}$
Có: `\sqrt{x}\ge0, ∀x≥0 `
`⇒\sqrt{x}+2\ge2`
`⇒ P\ge1-3/2`
`⇒P\ge-1/2.`
Dấu ''='' xảy ra khi `\sqrt{x}=0⇔x=0`
Vậy $\min P$ `=-1/2⇔x=0.`