Đáp án:
Giải thích các bước giải:
(9-6x)×(16+x)=0
⇔\(\left[ \begin{array}{l}9-6x=0\\16+x=0\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=\frac{3}{2}\\x=-16\end{array} \right.\)
-13×[9x-(-21)]=0
⇔-13×(9x+21)=0
⇔9x+21=0
⇔9x=-21
⇔x=$\frac{-7}{3}$
9x × (-14-11x)=0
⇔\(\left[ \begin{array}{l}9x=0\\-14-11x=0\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=0\\x=\frac{-14}{11} \end{array} \right.\)
