\(\left|3,5-x\right|+\dfrac{2}{7}=\dfrac{16}{7}\) \(\left|3,5-x\right|=\dfrac{16}{7}-\dfrac{2}{7}\) \(\left|3,5-x\right|=\dfrac{14}{7}\) \(\left|3,5-x\right|=2\) => \(3,5-x=2hoặc3,5-x=-2\) \(x=3,5-2\) hoặc \(x=3,5-\left(-2\right)\) \(x=1,5\) hoặc \(x=3,5+2\) \(x=1,5\) hoặc \(x=5,5\) Vậy x=1,5 hoặc x=5,5