A.5B.7C.4D.3
A.\(16\)B.\(8\) C.\(2\) D.\(4\)
A.7B.6C.4D.5
A.\({S_{xq}} = 9\pi \)B.\({S_{xq}} = \dfrac{{9\pi }}{2}\)C.\({S_{xq}} = \dfrac{{9\sqrt 2 \pi }}{4}\) D.\({S_{xq}} = \dfrac{{9\pi \sqrt 2 }}{2}\)
A.2B.\(\dfrac{1}{2}\) C.3D.\(\dfrac{1}{3}\)
A.3B.1C.2D.4
A.\(\overrightarrow {{u_1}} = \left( {0; - 1; - 2} \right)\)B.\(\overrightarrow {{u_2}} = \left( {2; - 1;0} \right)\)C.\(\overrightarrow {{u_3}} = \left( { - 1;0;1} \right)\) D.\(\overrightarrow {{u_4}} = \left( { - 1;1; - 1} \right)\)
A.\( - 101376\)B.25344. C.101376. D.\( - 25344\)
A.\(2.\)B.\(4.\) C.\(3.\) D.\(1.\)
A.\(\dfrac{{x - 1}}{1} = \dfrac{y}{1} = \dfrac{{z - 1}}{{ - 1}}\)B.\(\dfrac{{x + 1}}{{ - 1}} = \dfrac{{y + 1}}{{ - 1}} = \dfrac{{z - 2}}{1}\)C.\(\dfrac{{x - 1}}{1} = \dfrac{{y - 2}}{1} = \dfrac{{z - 3}}{{ - 1}}\) \(\)D.\(\dfrac{{x - 1}}{1} = \dfrac{y}{{ - 1}} = \dfrac{{z - 1}}{1}\)
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