Đáp án:
`x=1`
Giải thích các bước giải:
Ta có :
`(2x-1)^{2020}=(2x-1)^{2021}`
`→(2x-1)^{2020}-(2x-1)^{2021}=0`
`→(2x-1)^{2020}[1-(2x-1)]=0`
`→(2x-1)^{2020}(1-2x+1)=0`
`→(2x-1)^{2020}(2-2x)=0`
`→` \(\left[ \begin{array}{l}(2x-1)^{2020}=0\\2-2x=0\end{array} \right.\)
`→` \(\left[ \begin{array}{l}2x-1=0\\2(1-x)=0\end{array} \right.\)
`→` \(\left[ \begin{array}{l}2x=1\\1-x=0\end{array} \right.\)
`→` \(\left[ \begin{array}{l}x=\frac{1}{2}\\x=1\end{array} \right.\)
Mà `x∈N`
`→x=1`
