Ta có: \(3n+2⋮n-1\)
\(\Leftrightarrow3n-3+5⋮n-1\)
Mà: \(3n-3⋮n-1\)
\(\Rightarrow5⋮n-1\Leftrightarrow n-1\inƯ_{\left(5\right)}\left\{-5;-1;1;5\right\}\)
\(\Leftrightarrow\left[{}\begin{matrix}n-1=-5\-1=-1\-1=1\-1=5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}n=-4\=0\=2\=6\end{matrix}\right.\)
Vậy:\(n=-4;0;2;6\)
_Chúc bạn học tốt_
