`(n+10)/(2n-8) nguyên ⇔ n+10 vdots 2n-8 ⇔ 2n+20 vdots 2n-8`
`⇔ (2n+20)-(2n-8) vdots 2n-8 ⇔ 2n+20-2n+8 vdots 2n-8`
`⇔ 28 vdots 2n-8 `
Do `2n` chẵn `=> 2n-8` chẵn
`⇔ 2n-8 ∈ Ư(28) = {2;4;14;28;-2;-4;-14;-28}`
`⇔ 2n ∈ {10;12;22;36;6;4;-6;-20}`
`⇔ n ∈ {5;6;11;18;3;2;-3;-10}`
(Chúc bạn học tốt)