Cho $f(x)=0$
$⇔|3-|x-1||-2x=0$
$⇔|3-|x-1||=2x$
⇔\(\left[ \begin{array}{l}3-|x-1|=2x\\3-|x-1|=-2x\end{array} \right.\)
⇔\(\left[ \begin{array}{l}|x-1|=3-2x\\|x-1|=3+2x\end{array} \right.\)
⇔$x-1=3-2x$ hoặc $x-1=2x-3(l)$ hoặc $x-1=3+2x(l)$ hoặc $x-1=-3-2x(l)$
⇔$x=4/3$