Giải thích các bước giải:
Ta có :
$6x^2-2xy=3y-11x+2$
$\to 2xy+3y=6x^2+11x-2$
$\to y(2x+3)=(6x^2+9x)+(2x+3)-5$
$\to y(2x+3)=3x(2x+3)+(2x+3)-5$
$\to y=3x+1-\dfrac{5}{2x+3}$
$\to 5\quad\vdots\quad 2x+3$
$\to 2x+3\in\{1,5,-1,-5\}$
$\to 2x\in\{-2,2,-4,-8\}$
$\to x\in\{-1,1,-2,-4\}$
$\to y\in\{-7,3,0,-10\}$