@Thỏ
a) $(2x - 3)^{2}$ = `16`
⇒ $(2x - 3)^{2}$ = $4^{2}$
⇒ \(\left[ \begin{array}{1}2x - 3 = 4\\2x - 3 = -4\end{array} \right.\)
⇒ \(\left[ \begin{array}{l}2x = 7\\2x = -1\end{array} \right.\)
⇒ \(\left[ \begin{array}{l}x=\frac{7}{2} \\x= \frac{-1}{2} \end{array} \right.\)
b) $(3x - 2)^{5}$ = -`243`
⇒ $(3x - 2)^{5}$ = $-3^{5}$
⇒ $3x - 2^{}$ = -`3`
⇒ $3x^{}$ = -`1`
⇒ `x` = `-1/3`