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`1/(x-1)+(-2)/3 (3/4 - 6/5) =5/(2-2x) (x \ne 1)`
`=> 2/(2x-2) + (-2)/3 . (-9)/20 -5/(2-2x)=0`
`=> - 2/(2-2x) + 3/10 -5/(2-2x)=0`
`=> (- 2/(2-2x)-5/(2-2x)) +3/10=0`
`=> (-7)/(2-2x) = (-3)/10`
`=> -7 = (-3)/10 (2-2x)`
`=> 2-2x=70/3`
`=> 2x=(-64)/3`
`=>x=(-32)/3` (Thỏa mãn)
Vậy `x=(-32)/3`