Ta có :
( -4$\frac{1}{3}$ .($\frac{1}{2}$ - $\frac{1}{6}$ )
=($\frac{13}{3}$ ).$\frac{2}{6}$
= (-$\frac{26}{18}$ )
(-$\frac{2}{3}$ ).($\frac{1}{3}$ - $\frac{1}{2}$ - $\frac{3}{4}$ )
=(-$\frac{2}{3}$ ).($\frac{4}{12}$ - $\frac{6}{12}$ -$\frac{9}{12}$ )
=(-$\frac{2}{3}$) .($\frac{4-6-9}{12}$ )
=(-$\frac{2}{3}$ ).$\frac{-11}{12}$
=$\frac{22}{36}$ =$\frac{11}{18}$
Ta có :
(-$\frac{26}{180}$ ) `≤ x ≤ → x ∈ { -2 , - 1 , 0 }`
Vậy `x ∈ {-2 ,-1 , 0 }`