Đáp án:
Giải thích các bước giải:
ta có:
(2x+1)(y-3)=2
ta có:
⇒\(\left[ \begin{array}{l}2x+1=2\\y-3=1\end{array} \right.\)
\(\left[ \begin{array}{l}2x+1=1\\y-3=2\end{array} \right.\)
\(\left[ \begin{array}{l}2x+1=-2\\y-3=-1\end{array} \right.\)
\(\left[ \begin{array}{l}2x+1=-1\\y-3=-2\end{array} \right.\)
⇒\(\left[ \begin{array}{l}2x=1\\y=4\end{array} \right.\)
\(\left[ \begin{array}{l}2x=0\\y=5\end{array} \right.\)
\(\left[ \begin{array}{l}2x=-3\\y=2\end{array} \right.\)
\(\left[ \begin{array}{l}2x=-2\\y=1\end{array} \right.\)
⇒\(\left[ \begin{array}{l}x=\frac{1}{2} \\y=4\end{array} \right.\)
\(\left[ \begin{array}{l}x=0\\y=5\end{array} \right.\)
\(\left[ \begin{array}{l}x=\frac{-3}{2} \\y=2\end{array} \right.\)
\(\left[ \begin{array}{l}x=-1\\y=1\end{array} \right.\)