Tham khảo
` xy-x+2y=5`
`⇒x(y-1)+(2y-2)=5-2`
`⇒x(y-1)+2(y-1)=3`
`⇒(y-1)(x+2)=3`
`⇒y-1,x+2∈Ư(3)={±1,±3}`
Ta có bảng:
$\left[\begin{array}{ccc}y-1&1&-1&3&-3\\y&2&0&4&-2\\x+2&3&-3&1&-1\\x&1&-5&-1&-3\end{array}\right]$
Vậy `(x,y)=(1,2);(-5,0);(-1,4);(-3,-2)`
`\text{©CBT}`