|x - $\frac{25}{3}$| - 2 = $\frac{7}{3}$
|x - $\frac{25}{3}$| = $\frac{7}{3}$ + 2
|x - $\frac{25}{3}$| = $\frac{7}{3}$ + $\frac{6}{3}$
|x - $\frac{25}{3}$| = $\frac{13}{3}$
TH1: x - $\frac{25}{3}$ = $\frac{13}{3}$
x = $\frac{13}{3}$ + $\frac{25}{3}$
x = $\frac{38}{3}$
TH2: x - $\frac{25}{3}$ = $\frac{-13}{3}$
x = $\frac{-13}{3}$ + $\frac{25}{3}$
x = 4
Vậy x ∈ {$\frac{38}{3}$; 4}
