$\text{[3⁴-(8²+14):13]x=5³+10²}$
$\text{=[81−1 . (64+14)13]𝑥=$5^{3}$ + $10^{2}$ }$
$\text{=[81−1 ⋅ (64+14) : 13] x= $5^{3}$ + $10^{2}$ }$
$\text{=[81−1 ⋅ (78) : 13] x= $5^{3}$ + $10^{2}$ }$
$\text{=[81−1 ⋅ 6] x= $5^{3}$ + $10^{2}$ }$
$\text{= [81−6] x= $5^{3}$ + $10^{2}$ }$
$\text{=[75]x= $5^{3}$ + $10^{2}$}$
$\text{=75x=125+100}$
$\text{=75x=225}$
$\text{=$\frac{75x}{75}$ = $\frac{225}{75}$ }$
$\text{x=$\frac{225}{75}$ }$
$\text{ x = 3}$
$\text{Vậy x=3}$
$\text{#Karis257}$
