$10$ $\vdots$ $(2x+1)$
$⇒2x+1 ∈ Ư(10)$
$\textrm{Ư(10) = {1; -1; 2; -2; 5; -5; 10; -10}}$
$2x+1=1⇒x=0$
$2x+1=-1⇒x=-1$
$2x+1=2⇒x=\frac{1}{2}$
$2x+1=-2⇒x=\frac{-3}{2}$
$2x+1=5⇒x=2$
$2x+1=-5⇒x=-3$
$2x+1=10⇒x=\frac{9}{2}$
$2x+1=-10⇒x=\frac{-11}{2}$
Mà $x$ $\neq$ $0$
$\textrm{⇒ x = {-1; 2; -3}}$