Đáp án:
\(m \in \left\{ {0;1} \right\}\)
Giải thích các bước giải:
\(\begin{array}{l}
\left\{ \begin{array}{l}
\dfrac{{39}}{{52}} - \dfrac{1}{2} - \dfrac{3}{4} \le 4m\\
4m \le \dfrac{{89}}{{11}} - \left( {\dfrac{{ - 6}}{{11}} + 2} \right)
\end{array} \right.\\
\to \left\{ \begin{array}{l}
\dfrac{{39 - 26 - 3.13}}{{52}} \le 4m\\
4m \le \dfrac{{89}}{{11}} - \left( {\dfrac{{ - 6 + 22}}{{11}}} \right)
\end{array} \right.\\
\to \left\{ \begin{array}{l}
\dfrac{{ - 26}}{{52}} \le 4m\\
4m \le \dfrac{{89 - 16}}{{11}}
\end{array} \right.\\
\to \left\{ \begin{array}{l}
- \dfrac{1}{2} \le 4m\\
4m \le \dfrac{{73}}{{11}}
\end{array} \right.\\
\to - \dfrac{1}{8} \le m \le \dfrac{{73}}{{44}}\\
Do:m \in Z\\
\to m \in \left\{ {0;1} \right\}
\end{array}\)
