Đáp án:
$\begin{array}{l}
3\dfrac{1}{3}:2\dfrac{1}{2} - 1 < x < 7\dfrac{2}{3}.\dfrac{3}{7} + \dfrac{5}{2}\\
\Rightarrow \dfrac{{10}}{3}:\dfrac{5}{2} - 1 < x < \dfrac{{23}}{3}.\dfrac{3}{7} + \dfrac{5}{2}\\
\Rightarrow \dfrac{{10}}{3}.\dfrac{2}{5} - 1 < x < \dfrac{{23}}{7} + \dfrac{5}{2}\\
\Rightarrow \dfrac{4}{3} - 1 < x < \dfrac{{23.2 + 5.7}}{{7.2}}\\
\Rightarrow \dfrac{1}{3} < x < \dfrac{{81}}{{14}}\\
\Rightarrow 0,333 < x < 5,78\\
\Rightarrow \left[ \begin{array}{l}
x = 1\\
x = 2\\
x = 3\\
x = 4\\
x = 5
\end{array} \right.\\
Vậy\,x \in \left\{ {1;2;3;4;5} \right\}
\end{array}$
