`A=(10x+7)/(5n-1) in Z`
`=>10x+7` $\vdots$ `5n-1`
`=>10x-2+9` $\vdots$ `5n-1`
`=>2(5n-1)+9` $\vdots$ `5n-1`
`=>9` $\vdots$ `5n-1` vì `2(5n-1)` $\vdots$ `5n-1`
`=>5n-1 in Ư(9)={+-1,+-3,+-9}`
Vì `5n-1` là số +1 chia hết cho 5
`=>5n-1 in {-1,9}`
`=>5n in {0,10}`
`=> n in {0,2}`
Vậy `n in {0,2}`