a) ${|x|-3=0}$
${|x|=0+3=3}$
${=>}$\(\left[ \begin{array}{l}x=3\\x=-3\end{array} \right.\)
b) ${(7-|x|).(2x-4)=0}$
⇔ \(\left[ \begin{array}{l}7-|x|=0\\2x-4=0\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}|x|=7-0=7\\2x=0+4=4\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}x=±7\\x=2\end{array} \right.\)