c,(x+7)(x-9)=0
⇒ \(\left[ \begin{array}{l}x+7=0\\x-9=0\end{array} \right.\)
⇒ \(\left[ \begin{array}{l}x=-7\\x=9\end{array} \right.\)
Vậy x ∈ {-7; 9}
d,|2x-5|-7=22
⇒ |2x-5| = 22 +7
⇒ |2x-5| = 29
⇒ \(\left[ \begin{array}{l}2x-5=29\\2x-5=-29\end{array} \right.\)
⇒ \(\left[ \begin{array}{l}x=17\\x=-12\end{array} \right.\)
Vậy x ∈ {17; -12}