Đáp án:
Giải thích các bước giải:
a) $(x-3)(y+5)=-17\\\Leftrightarrow y=-\frac{17}{x-3}-5\\\Rightarrow 17\vdots x-3\\\Leftrightarrow x\in \{2; 4; -14; 20\}\\\Leftrightarrow (x; y)\in \{(2; 12); (4; -22); (-14; -4); (20; -6)\}$
b) $(x+1)(xy-2)=11\\\Leftrightarrow y=\frac{\frac{11}{x+1}+2}{x}=\frac{2x^2+15x}{x+2}=\frac{x(2x+15)}{x+2}\\TH1: x\vdots x+2\\\Leftrightarrow x\in \{-3; -1; -4; 0\}\\TH2: 2x+15\vdots x+2\\\Leftrightarrow x\in \{-3; -1; -13; 9\}\\\Rightarrow x\in \{-3; -1; -4; 0; -13; 9\}\\\Leftrightarrow (x; y)\in \{(-3; 27); (-1; -13); (-4; 14); (0; 0); (-13; -13); (9; 27)\}$
