Bạn tham khảo!
$2x$ $=$ $3y$ $=$ $5z$ và $x$ $+$ $y$ $+$ $z$ $=$ $95$
Ta có : $2x$ $=$ $3y$ $=$ $5z$
$→$ $\dfrac{2x}{30}$ $=$ $\dfrac{3y}{30}$ $=$ $\dfrac{5z}{30}$
$→$ $\dfrac{x}{15}$ $=$ $\dfrac{y}{10}$ $=$ $\dfrac{z}{6}$
Áp dụng t/c dãy tỉ số $=$ nhau ta có :
$\dfrac{x}{15}$ $=$ $\dfrac{y}{10}$ $=$ $\dfrac{z}{6}$ $=$ $\dfrac{x+y+z}{15+10+6}$ $=$ $\dfrac{95}{31}$
$→$ $\dfrac{x}{15}$ $=$ $\dfrac{95}{31}$ $→$ $x$ $=$ $\dfrac{1425}{31}$
và $\dfrac{y}{10}$ $=$ $\dfrac{95}{31}$ $→$ $y$ $=$ $\dfrac{950}{31}$
và $\dfrac{z}{6}$ $=$ $\dfrac{96}{31}$ $→$ $z$ $=$ $\dfrac{570}{31}$
Vậy $x$ $=$ $\dfrac{1425}{31}$ $;$ $y$ $=$ $\dfrac{950}{31}$ và $z$ $=$ $\dfrac{570}{31}$
$FbBinhne2k88$
