Đáp án:
Ta có: Viết đề:
⇒$\frac{4(3x-2y)}{16}$ =$\frac{3(2z-4x)}{9}$ =$\frac{2(4y-3z)}{4}$
=$\frac{12x-8y+6z-12x+8y-6z}{29}$ =0
Do đó :$\frac{3x-2y}{4}$ =0⇒3x=2y⇔$\frac{x}{2}$ =$\frac{y}{3}$ (1)
$\frac{2z-4x}{3}$ =0⇒$\frac{x}{2}$ =$\frac{z}{4}$ (2)
Từ(1)(2)⇒$\frac{x}{2}$ =$\frac{y}{3}$ =$\frac{z}{4}$
Adtctc:......................................................................................
=$\frac{x+y+z}{2+3+4}$ =$\frac{18}{9}$ =3
⇒x=4
y=6
z=8
