$\dfrac{x}{3}=\dfrac{y}{4}→\dfrac{2x}{6}=\dfrac{5y}{20}$
Áp dụng tính chất dãy tỉ số bằng nhau:
$\dfrac{2x}{6}=\dfrac{5y}{20}=\dfrac{2x+5y}{6+20}=\dfrac{10}{26}$
\(→\left[ \begin{array}{l}\dfrac{x}{3}=\dfrac{10}{26}→x=\dfrac{10}{26}.3=\dfrac{15}{13}\\\dfrac{y}{4}=\dfrac{10}{26}→y=\dfrac{10}{26}.4=\dfrac{20}{13}\end{array} \right.\)