Đáp án:
Giải thích các bước giải:
$7$ $\vdots$ $x+1$
$⇒x+1∈${$7;1;-1;-7$}
$⇒x∈${$6;0;-2;-8$}
$ $
$x+14$ $\vdots$ $x+3$
$⇒(x+3)+11$ $\vdots$ $x+3$
$⇒11$ $\vdots$ $x+3$
$⇒x+3∈${$11;1;-1;-11$}
$⇒x∈${$8;-2;-4;-14$}
$ $
$2x+1$ $\vdots$ $x-2$
$⇒2x-4+4+1$ $\vdots$ $x-2$
$⇒2.(x-2)+5$ $\vdots$ $x-2$
$⇒5$ $\vdots$ $x-2$
$⇒x-2∈${$5;1;-1;-5$}
$⇒x∈${$7;3;1;-3$}