$\frac{2003 .14+ 1988+ 2001.2002}{2002+ 2002.503+ 504 .2002}$
$=\frac{(2002+1) .14+ 1988+ 2001.2002}{2002.(1+503+ 504 )}$
$=\frac{2002.14+(14+1988)+2001.2002}{2002.1008}$
$=\frac{2002.(14+1+2001)}{2002.1008}$
$=\frac{2002.2016}{2002.1008}$
$=\frac{2016}{1008}$
$=2$